60=(2x-10)(x-4)

Solution for 60=(2x-10)(x-4) equation:

60=(2x-10)(x-4)

We move all terms to the left:

60-((2x-10)(x-4))=0

We multiply parentheses ..

-((+2x^2-8x-10x+40))+60=0


We calculate terms in parentheses: -((+2x^2-8x-10x+40)), so:

(+2x^2-8x-10x+40)

We get rid of parentheses

2x^2-8x-10x+40

We add all the numbers together, and all the variables

2x^2-18x+40

Back to the equation:

-(2x^2-18x+40)


We get rid of parentheses

-2x^2+18x-40+60=0

We add all the numbers together, and all the variables

-2x^2+18x+20=0

a = -2; b = 18; c = +20;
Δ = b2-4ac
Δ = 182-4·(-2)·20
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-22}{2*-2}=\frac{-40}{-4}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+22}{2*-2}=\frac{4}{-4}
=-1
$