60=-10(2z-6)+20z

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Solution for 60=-10(2z-6)+20z equation: 



60=-10(2z-6)+20z

We move all terms to the left:

60-(-10(2z-6)+20z)=0



We calculate terms in parentheses: -(-10(2z-6)+20z), so:

-10(2z-6)+20z

We add all the numbers together, and all the variables

20z-10(2z-6)

We multiply parentheses

20z-20z+60

We add all the numbers together, and all the variables

60

Back to the equation:

-(60)



We add all the numbers together, and all the variables

=0

z=0/1

z=0

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