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60=1/2(x+3)(x-8)
We move all terms to the left:
60-(1/2(x+3)(x-8))=0
Domain of the equation: 2(x+3)(x-8))!=0We multiply parentheses ..
x∈R
-(1/2(+x^2-8x+3x-24))+60=0
We multiply all the terms by the denominator
-(1+60*2(+x^2-8x+3x-24))=0
We calculate terms in parentheses: -(1+60*2(+x^2-8x+3x-24)), so:We add all the numbers together, and all the variables
1+60*2(+x^2-8x+3x-24)
determiningTheFunctionDomain 60*2(+x^2-8x+3x-24)+1
Wy multiply elements
120x(++1
We use the square of the difference formula
120x(+1
Back to the equation:
-(120x(+1)
-(120x1=0
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