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60=2x(x+1)
We move all terms to the left:
60-(2x(x+1))=0
We calculate terms in parentheses: -(2x(x+1)), so:We get rid of parentheses
2x(x+1)
We multiply parentheses
2x^2+2x
Back to the equation:
-(2x^2+2x)
-2x^2-2x+60=0
a = -2; b = -2; c = +60;
Δ = b2-4ac
Δ = -22-4·(-2)·60
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-22}{2*-2}=\frac{-20}{-4} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+22}{2*-2}=\frac{24}{-4} =-6 $
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