60=3x(x+6)

Solution for 60=3x(x+6) equation:

60=3x(x+6)

We move all terms to the left:

60-(3x(x+6))=0


We calculate terms in parentheses: -(3x(x+6)), so:

3x(x+6)

We multiply parentheses

3x^2+18x

Back to the equation:

-(3x^2+18x)


We get rid of parentheses

-3x^2-18x+60=0

a = -3; b = -18; c = +60;
Δ = b2-4ac
Δ = -182-4·(-3)·60
Δ = 1044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1044}=\sqrt{36*29}=\sqrt{36}*\sqrt{29}=6\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6\sqrt{29}}{2*-3}=\frac{18-6\sqrt{29}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6\sqrt{29}}{2*-3}=\frac{18+6\sqrt{29}}{-6}
$