60=4(k+3)+(2-3)

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Solution for 60=4(k+3)+(2-3) equation: 



60=4(k+3)+(2-3)

We move all terms to the left:

60-(4(k+3)+(2-3))=0

We add all the numbers together, and all the variables

-(4(k+3)+(-1))+60=0



We calculate terms in parentheses: -(4(k+3)+(-1)), so:

4(k+3)+(-1)

We add all the numbers together, and all the variables

4(k+3)-1

We multiply parentheses

4k+12-1

We add all the numbers together, and all the variables

4k+11

Back to the equation:

-(4k+11)



We get rid of parentheses

-4k-11+60=0

We add all the numbers together, and all the variables

-4k+49=0

We move all terms containing k to the left, all other terms to the right

-4k=-49

k=-49/-4

k=12+1/4

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