60=4(k+3)+2+(k-3)

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Solution for 60=4(k+3)+2+(k-3) equation: 



60=4(k+3)+2+(k-3)

We move all terms to the left:

60-(4(k+3)+2+(k-3))=0



We calculate terms in parentheses: -(4(k+3)+2+(k-3)), so:

4(k+3)+2+(k-3)

determiningTheFunctionDomain
4(k+3)+(k-3)+2

We multiply parentheses

4k+(k-3)+12+2

We get rid of parentheses

4k+k-3+12+2

We add all the numbers together, and all the variables

5k+11

Back to the equation:

-(5k+11)



We get rid of parentheses

-5k-11+60=0

We add all the numbers together, and all the variables

-5k+49=0

We move all terms containing k to the left, all other terms to the right

-5k=-49

k=-49/-5

k=9+4/5

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