60=4(k+3)=10

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Solution for 60=4(k+3)=10 equation: 



60=4(k+3)=10

We move all terms to the left:

60-(4(k+3))=0



We calculate terms in parentheses: -(4(k+3)), so:

4(k+3)

We multiply parentheses

4k+12

Back to the equation:

-(4k+12)



We get rid of parentheses

-4k-12+60=0

We add all the numbers together, and all the variables

-4k+48=0

We move all terms containing k to the left, all other terms to the right

-4k=-48

k=-48/-4

k=+12

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