60=4(k/3)+2(k-3)

Solution for 60=4(k/3)+2(k-3) equation:

60=4(k/3)+2(k-3)

We move all terms to the left:

60-(4(k/3)+2(k-3))=0


Domain of the equation: 3)+2(k-3))!=0

k∈R


We add all the numbers together, and all the variables

-(4(+k/3)+2(k-3))+60=0

We multiply all the terms by the denominator


-(4(+k+60*3)+2(k-3))=0


We calculate terms in parentheses: -(4(+k+60*3)+2(k-3)), so:

4(+k+60*3)+2(k-3)

We add all the numbers together, and all the variables

4(k+180)+2(k-3)

We multiply parentheses

4k+2k+720-6

We add all the numbers together, and all the variables

6k+714

Back to the equation:

-(6k+714)


We get rid of parentheses

-6k-714=0

We move all terms containing k to the left, all other terms to the right

-6k=714

k=714/-6

k=-119