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60=43+(2n-5)
We move all terms to the left:
60-(43+(2n-5))=0
We calculate terms in parentheses: -(43+(2n-5)), so:We get rid of parentheses
43+(2n-5)
determiningTheFunctionDomain (2n-5)+43
We get rid of parentheses
2n-5+43
We add all the numbers together, and all the variables
2n+38
Back to the equation:
-(2n+38)
-2n-38+60=0
We add all the numbers together, and all the variables
-2n+22=0
We move all terms containing n to the left, all other terms to the right
-2n=-22
n=-22/-2
n=+11
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