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60=5x(3x-1)
We move all terms to the left:
60-(5x(3x-1))=0
We calculate terms in parentheses: -(5x(3x-1)), so:We get rid of parentheses
5x(3x-1)
We multiply parentheses
15x^2-5x
Back to the equation:
-(15x^2-5x)
-15x^2+5x+60=0
a = -15; b = 5; c = +60;
Δ = b2-4ac
Δ = 52-4·(-15)·60
Δ = 3625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3625}=\sqrt{25*145}=\sqrt{25}*\sqrt{145}=5\sqrt{145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{145}}{2*-15}=\frac{-5-5\sqrt{145}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{145}}{2*-15}=\frac{-5+5\sqrt{145}}{-30} $
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