60x-48-20(5x-4)=20

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Solution for 60x-48-20(5x-4)=20 equation: 



60x-48-20(5x-4)=20

We move all terms to the left:

60x-48-20(5x-4)-(20)=0

We add all the numbers together, and all the variables

60x-20(5x-4)-68=0

We multiply parentheses

60x-100x+80-68=0

We add all the numbers together, and all the variables

-40x+12=0

We move all terms containing x to the left, all other terms to the right

-40x=-12

x=-12/-40

x=3/10

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