60x-48-20(5x-4)=20

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Solution for 60x-48-20(5x-4)=20 equation:



60x-48-20(5x-4)=20
We move all terms to the left:
60x-48-20(5x-4)-(20)=0
We add all the numbers together, and all the variables
60x-20(5x-4)-68=0
We multiply parentheses
60x-100x+80-68=0
We add all the numbers together, and all the variables
-40x+12=0
We move all terms containing x to the left, all other terms to the right
-40x=-12
x=-12/-40
x=3/10

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