60x2+x=10

Solution for 60x2+x=10 equation:

60x^2+x=10

We move all terms to the left:

60x^2+x-(10)=0

a = 60; b = 1; c = -10;
Δ = b2-4ac
Δ = 12-4·60·(-10)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-49}{2*60}=\frac{-50}{120}
=-5/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+49}{2*60}=\frac{48}{120}
=2/5
$