60x2+x=10

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Solution for 60x2+x=10 equation:



60x^2+x=10
We move all terms to the left:
60x^2+x-(10)=0
a = 60; b = 1; c = -10;
Δ = b2-4ac
Δ = 12-4·60·(-10)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-49}{2*60}=\frac{-50}{120} =-5/12 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+49}{2*60}=\frac{48}{120} =2/5 $

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