60y2-20y-5=0

Solution for 60y2-20y-5=0 equation:

60y^2-20y-5=0

a = 60; b = -20; c = -5;
Δ = b2-4ac
Δ = -202-4·60·(-5)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-40}{2*60}=\frac{-20}{120}
=-1/6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+40}{2*60}=\frac{60}{120}
=1/2
$