61-x+5=2(x+3)+6(x+1)

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Solution for 61-x+5=2(x+3)+6(x+1) equation: 



61-x+5=2(x+3)+6(x+1)

We move all terms to the left:

61-x+5-(2(x+3)+6(x+1))=0

We add all the numbers together, and all the variables

-1x-(2(x+3)+6(x+1))+66=0



We calculate terms in parentheses: -(2(x+3)+6(x+1)), so:

2(x+3)+6(x+1)

We multiply parentheses

2x+6x+6+6

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

-1x-8x-12+66=0

We add all the numbers together, and all the variables

-9x+54=0

We move all terms containing x to the left, all other terms to the right

-9x=-54

x=-54/-9

x=+6

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