61=1/2(10x+1-5x-1)

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Solution for 61=1/2(10x+1-5x-1) equation: 



61=1/2(10x+1-5x-1)

We move all terms to the left:

61-(1/2(10x+1-5x-1))=0



Domain of the equation: 2(10x+1-5x-1))!=0

x∈R



We add all the numbers together, and all the variables

-(1/2(+5x))+61=0

We multiply all the terms by the denominator


-(1+61*2(+5x))=0



We calculate terms in parentheses: -(1+61*2(+5x)), so:

1+61*2(+5x)

determiningTheFunctionDomain
61*2(+5x)+1

Wy multiply elements

122x(++1

We use the square of the difference formula

122x(+1

Back to the equation:

-(122x(+1)



We add all the numbers together, and all the variables

-(122x1=0

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