61=3(7-5a)-5(a-4)

Solution for 61=3(7-5a)-5(a-4) equation:

61=3(7-5a)-5(a-4)

We move all terms to the left:

61-(3(7-5a)-5(a-4))=0

We add all the numbers together, and all the variables

-(3(-5a+7)-5(a-4))+61=0


We calculate terms in parentheses: -(3(-5a+7)-5(a-4)), so:

3(-5a+7)-5(a-4)

We multiply parentheses

-15a-5a+21+20

We add all the numbers together, and all the variables

-20a+41

Back to the equation:

-(-20a+41)


We get rid of parentheses

20a-41+61=0

We add all the numbers together, and all the variables

20a+20=0

We move all terms containing a to the left, all other terms to the right

20a=-20

a=-20/20

a=-1