61y=20(3y+12)

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Solution for 61y=20(3y+12) equation: 



61y=20(3y+12)

We move all terms to the left:

61y-(20(3y+12))=0



We calculate terms in parentheses: -(20(3y+12)), so:

20(3y+12)

We multiply parentheses

60y+240

Back to the equation:

-(60y+240)



We get rid of parentheses

61y-60y-240=0

We add all the numbers together, and all the variables

y-240=0

We move all terms containing y to the left, all other terms to the right

y=240

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