62-(7x+11)=7(x+3)+x

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Solution for 62-(7x+11)=7(x+3)+x equation: 



62-(7x+11)=7(x+3)+x

We move all terms to the left:

62-(7x+11)-(7(x+3)+x)=0

We get rid of parentheses

-7x-(7(x+3)+x)-11+62=0



We calculate terms in parentheses: -(7(x+3)+x), so:

7(x+3)+x

We add all the numbers together, and all the variables

x+7(x+3)

We multiply parentheses

x+7x+21

We add all the numbers together, and all the variables

8x+21

Back to the equation:

-(8x+21)



We add all the numbers together, and all the variables

-7x-(8x+21)+51=0

We get rid of parentheses

-7x-8x-21+51=0

We add all the numbers together, and all the variables

-15x+30=0

We move all terms containing x to the left, all other terms to the right

-15x=-30

x=-30/-15

x=+2

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