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62.5=(2x+2.5)x
We move all terms to the left:
62.5-((2x+2.5)x)=0
We calculate terms in parentheses: -((2x+2.5)x), so:We get rid of parentheses
(2x+2.5)x
We multiply parentheses
2x^2+2.5x
Back to the equation:
-(2x^2+2.5x)
-2x^2-2.5x+62.5=0
a = -2; b = -2.5; c = +62.5;
Δ = b2-4ac
Δ = -2.52-4·(-2)·62.5
Δ = 506.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.5)-\sqrt{506.25}}{2*-2}=\frac{2.5-\sqrt{506.25}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.5)+\sqrt{506.25}}{2*-2}=\frac{2.5+\sqrt{506.25}}{-4} $
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