62/m=31,m=2

Solution for 62/m=31,m=2 equation:

62/m=31.m=2

We move all terms to the left:

62/m-(31.m)=0


Domain of the equation: m!=0

m∈R


We add all the numbers together, and all the variables

62/m-(+31.m)=0

We get rid of parentheses

62/m-31.m=0

We multiply all the terms by the denominator


-(31.m)*m+62=0

We add all the numbers together, and all the variables

-(+31.m)*m+62=0

We multiply parentheses

-31m^2+62=0

a = -31; b = 0; c = +62;
Δ = b2-4ac
Δ = 02-4·(-31)·62
Δ = 7688
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7688}=\sqrt{3844*2}=\sqrt{3844}*\sqrt{2}=62\sqrt{2}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-62\sqrt{2}}{2*-31}=\frac{0-62\sqrt{2}}{-62}
=-\frac{62\sqrt{2}}{-62}
=-\frac{\sqrt{2}}{-1}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+62\sqrt{2}}{2*-31}=\frac{0+62\sqrt{2}}{-62}
=\frac{62\sqrt{2}}{-62}
=\frac{\sqrt{2}}{-1}
$