62/m=31,m=2

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Solution for 62/m=31,m=2 equation:



62/m=31.m=2
We move all terms to the left:
62/m-(31.m)=0
Domain of the equation: m!=0
m∈R
We add all the numbers together, and all the variables
62/m-(+31.m)=0
We get rid of parentheses
62/m-31.m=0
We multiply all the terms by the denominator
-(31.m)*m+62=0
We add all the numbers together, and all the variables
-(+31.m)*m+62=0
We multiply parentheses
-31m^2+62=0
a = -31; b = 0; c = +62;
Δ = b2-4ac
Δ = 02-4·(-31)·62
Δ = 7688
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{7688}=\sqrt{3844*2}=\sqrt{3844}*\sqrt{2}=62\sqrt{2}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-62\sqrt{2}}{2*-31}=\frac{0-62\sqrt{2}}{-62} =-\frac{62\sqrt{2}}{-62} =-\frac{\sqrt{2}}{-1} $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+62\sqrt{2}}{2*-31}=\frac{0+62\sqrt{2}}{-62} =\frac{62\sqrt{2}}{-62} =\frac{\sqrt{2}}{-1} $

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