62=2l+2(2/3l)

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Solution for 62=2l+2(2/3l) equation: 



62=2l+2(2/3l)

We move all terms to the left:

62-(2l+2(2/3l))=0



Domain of the equation: 3l))!=0

l!=0/1

l!=0

l∈R



We add all the numbers together, and all the variables

-(2l+2(+2/3l))+62=0

We multiply all the terms by the denominator


-(2l+2(+2+62*3l))=0



We calculate terms in parentheses: -(2l+2(+2+62*3l)), so:

2l+2(+2+62*3l)

We add all the numbers together, and all the variables

2l+2(62*3l+2)

We multiply parentheses

2l+372l+4

We add all the numbers together, and all the variables

374l+4

Back to the equation:

-(374l+4)



We get rid of parentheses

-374l-4=0

We move all terms containing l to the left, all other terms to the right

-374l=4

l=4/-374

l=-2/187

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