62=2l+2(2/3l)

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Solution for 62=2l+2(2/3l) equation:



62=2l+2(2/3l)
We move all terms to the left:
62-(2l+2(2/3l))=0
Domain of the equation: 3l))!=0
l!=0/1
l!=0
l∈R
We add all the numbers together, and all the variables
-(2l+2(+2/3l))+62=0
We multiply all the terms by the denominator
-(2l+2(+2+62*3l))=0
We calculate terms in parentheses: -(2l+2(+2+62*3l)), so:
2l+2(+2+62*3l)
We add all the numbers together, and all the variables
2l+2(62*3l+2)
We multiply parentheses
2l+372l+4
We add all the numbers together, and all the variables
374l+4
Back to the equation:
-(374l+4)
We get rid of parentheses
-374l-4=0
We move all terms containing l to the left, all other terms to the right
-374l=4
l=4/-374
l=-2/187

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