62=3z+12+(z+1)+(2z+2)+11

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Solution for 62=3z+12+(z+1)+(2z+2)+11 equation:


Simplifying
62 = 3z + 12 + (z + 1) + (2z + 2) + 11

Reorder the terms:
62 = 3z + 12 + (1 + z) + (2z + 2) + 11

Remove parenthesis around (1 + z)
62 = 3z + 12 + 1 + z + (2z + 2) + 11

Reorder the terms:
62 = 3z + 12 + 1 + z + (2 + 2z) + 11

Remove parenthesis around (2 + 2z)
62 = 3z + 12 + 1 + z + 2 + 2z + 11

Reorder the terms:
62 = 12 + 1 + 2 + 11 + 3z + z + 2z

Combine like terms: 12 + 1 = 13
62 = 13 + 2 + 11 + 3z + z + 2z

Combine like terms: 13 + 2 = 15
62 = 15 + 11 + 3z + z + 2z

Combine like terms: 15 + 11 = 26
62 = 26 + 3z + z + 2z

Combine like terms: 3z + z = 4z
62 = 26 + 4z + 2z

Combine like terms: 4z + 2z = 6z
62 = 26 + 6z

Solving
62 = 26 + 6z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6z' to each side of the equation.
62 + -6z = 26 + 6z + -6z

Combine like terms: 6z + -6z = 0
62 + -6z = 26 + 0
62 + -6z = 26

Add '-62' to each side of the equation.
62 + -62 + -6z = 26 + -62

Combine like terms: 62 + -62 = 0
0 + -6z = 26 + -62
-6z = 26 + -62

Combine like terms: 26 + -62 = -36
-6z = -36

Divide each side by '-6'.
z = 6

Simplifying
z = 6

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