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62x+1/3x+725=624
We move all terms to the left:
62x+1/3x+725-(624)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
62x+1/3x+101=0
We multiply all the terms by the denominator
62x*3x+101*3x+1=0
Wy multiply elements
186x^2+303x+1=0
a = 186; b = 303; c = +1;
Δ = b2-4ac
Δ = 3032-4·186·1
Δ = 91065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(303)-\sqrt{91065}}{2*186}=\frac{-303-\sqrt{91065}}{372} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(303)+\sqrt{91065}}{2*186}=\frac{-303+\sqrt{91065}}{372} $
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