63+(2x-10)+102+(6x-19)=360

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Solution for 63+(2x-10)+102+(6x-19)=360 equation:



63+(2x-10)+102+(6x-19)=360
We move all terms to the left:
63+(2x-10)+102+(6x-19)-(360)=0
We add all the numbers together, and all the variables
(2x-10)+(6x-19)-195=0
We get rid of parentheses
2x+6x-10-19-195=0
We add all the numbers together, and all the variables
8x-224=0
We move all terms containing x to the left, all other terms to the right
8x=224
x=224/8
x=28

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