63+2x=1/3(-12x+9)-12

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Solution for 63+2x=1/3(-12x+9)-12 equation: 



63+2x=1/3(-12x+9)-12

We move all terms to the left:

63+2x-(1/3(-12x+9)-12)=0



Domain of the equation: 3(-12x+9)-12)!=0

x∈R



We multiply all the terms by the denominator


2x*3(-12x+9)+63*3(-12x+9)-12)-(1-12)=0

We add all the numbers together, and all the variables

2x*3(-12x+9)+63*3(-12x+9)-12)-(-11)=0

We add all the numbers together, and all the variables

2x*3(-12x+9)+63*3(-12x+9)=0

Wy multiply elements

6x^2(-+189x(-=0

We use the square of the difference formula

6x^2(-189x(-=0

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