63+45+(4x-11)=180

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Solution for 63+45+(4x-11)=180 equation: 



63+45+(4x-11)=180

We move all terms to the left:

63+45+(4x-11)-(180)=0

We add all the numbers together, and all the variables

(4x-11)-72=0

We get rid of parentheses

4x-11-72=0

We add all the numbers together, and all the variables

4x-83=0

We move all terms containing x to the left, all other terms to the right

4x=83

x=83/4

x=20+3/4

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