63/9b=7b

Solution for 63/9b=7b equation:

63/9b=7b

We move all terms to the left:

63/9b-(7b)=0


Domain of the equation: 9b!=0

b!=0/9

b!=0

b∈R


We add all the numbers together, and all the variables

-7b+63/9b=0

We multiply all the terms by the denominator


-7b*9b+63=0

Wy multiply elements

-63b^2+63=0

a = -63; b = 0; c = +63;
Δ = b2-4ac
Δ = 02-4·(-63)·63
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*-63}=\frac{-126}{-126}
=1
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*-63}=\frac{126}{-126}
=-1
$