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630=x(x+9)
We move all terms to the left:
630-(x(x+9))=0
We calculate terms in parentheses: -(x(x+9)), so:We get rid of parentheses
x(x+9)
We multiply parentheses
x^2+9x
Back to the equation:
-(x^2+9x)
-x^2-9x+630=0
We add all the numbers together, and all the variables
-1x^2-9x+630=0
a = -1; b = -9; c = +630;
Δ = b2-4ac
Δ = -92-4·(-1)·630
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-51}{2*-1}=\frac{-42}{-2} =+21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+51}{2*-1}=\frac{60}{-2} =-30 $
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