63=3n+7(n-2)

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Solution for 63=3n+7(n-2) equation: 



63=3n+7(n-2)

We move all terms to the left:

63-(3n+7(n-2))=0



We calculate terms in parentheses: -(3n+7(n-2)), so:

3n+7(n-2)

We multiply parentheses

3n+7n-14

We add all the numbers together, and all the variables

10n-14

Back to the equation:

-(10n-14)



We get rid of parentheses

-10n+14+63=0

We add all the numbers together, and all the variables

-10n+77=0

We move all terms containing n to the left, all other terms to the right

-10n=-77

n=-77/-10

n=7+7/10

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