63=3x+6(2x-2)

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Solution for 63=3x+6(2x-2) equation: 



63=3x+6(2x-2)

We move all terms to the left:

63-(3x+6(2x-2))=0



We calculate terms in parentheses: -(3x+6(2x-2)), so:

3x+6(2x-2)

We multiply parentheses

3x+12x-12

We add all the numbers together, and all the variables

15x-12

Back to the equation:

-(15x-12)



We get rid of parentheses

-15x+12+63=0

We add all the numbers together, and all the variables

-15x+75=0

We move all terms containing x to the left, all other terms to the right

-15x=-75

x=-75/-15

x=+5

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