63=3y+12

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Solution for 63=3y+12 equation: 



63=3y+12

We move all terms to the left:

63-(3y+12)=0

We get rid of parentheses

-3y-12+63=0

We add all the numbers together, and all the variables

-3y+51=0

We move all terms containing y to the left, all other terms to the right

-3y=-51

y=-51/-3

y=+17

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