63=6(2k+2)+3

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Solution for 63=6(2k+2)+3 equation: 



63=6(2k+2)+3

We move all terms to the left:

63-(6(2k+2)+3)=0



We calculate terms in parentheses: -(6(2k+2)+3), so:

6(2k+2)+3

We multiply parentheses

12k+12+3

We add all the numbers together, and all the variables

12k+15

Back to the equation:

-(12k+15)



We get rid of parentheses

-12k-15+63=0

We add all the numbers together, and all the variables

-12k+48=0

We move all terms containing k to the left, all other terms to the right

-12k=-48

k=-48/-12

k=+4

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