63=7(1+)4b

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Solution for 63=7(1+)4b equation: 



63=7(1+)4b

We move all terms to the left:

63-(7(1+)4b)=0

We add all the numbers together, and all the variables

-(704b)+63=0

We add all the numbers together, and all the variables

-704b+63=0

We move all terms containing b to the left, all other terms to the right

-704b=-63

b=-63/-704

b=63/704

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