63x*2,5x=19

Solution for 63x*2,5x=19 equation:

63x*2.5x=19

We move all terms to the left:

63x*2.5x-(19)=0

Wy multiply elements

126x^2-19=0

a = 126; b = 0; c = -19;
Δ = b2-4ac
Δ = 02-4·126·(-19)
Δ = 9576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9576}=\sqrt{36*266}=\sqrt{36}*\sqrt{266}=6\sqrt{266}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{266}}{2*126}=\frac{0-6\sqrt{266}}{252}
=-\frac{6\sqrt{266}}{252}
=-\frac{\sqrt{266}}{42}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{266}}{2*126}=\frac{0+6\sqrt{266}}{252}
=\frac{6\sqrt{266}}{252}
=\frac{\sqrt{266}}{42}
$