63x+7x*7x=16

Solution for 63x+7x*7x=16 equation:

63x+7x*7x=16

We move all terms to the left:

63x+7x*7x-(16)=0

Wy multiply elements

49x^2+63x-16=0

a = 49; b = 63; c = -16;
Δ = b2-4ac
Δ = 632-4·49·(-16)
Δ = 7105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7105}=\sqrt{49*145}=\sqrt{49}*\sqrt{145}=7\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-7\sqrt{145}}{2*49}=\frac{-63-7\sqrt{145}}{98}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+7\sqrt{145}}{2*49}=\frac{-63+7\sqrt{145}}{98}
$