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63x^2+44x-33=0
a = 63; b = 44; c = -33;
Δ = b2-4ac
Δ = 442-4·63·(-33)
Δ = 10252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10252}=\sqrt{4*2563}=\sqrt{4}*\sqrt{2563}=2\sqrt{2563}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-2\sqrt{2563}}{2*63}=\frac{-44-2\sqrt{2563}}{126} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+2\sqrt{2563}}{2*63}=\frac{-44+2\sqrt{2563}}{126} $
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