64(2-3y)=6(8y-1)+68

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Solution for 64(2-3y)=6(8y-1)+68 equation: 



64(2-3y)=6(8y-1)+68

We move all terms to the left:

64(2-3y)-(6(8y-1)+68)=0

We add all the numbers together, and all the variables

64(-3y+2)-(6(8y-1)+68)=0

We multiply parentheses

-192y-(6(8y-1)+68)+128=0



We calculate terms in parentheses: -(6(8y-1)+68), so:

6(8y-1)+68

We multiply parentheses

48y-6+68

We add all the numbers together, and all the variables

48y+62

Back to the equation:

-(48y+62)



We get rid of parentheses

-192y-48y-62+128=0

We add all the numbers together, and all the variables

-240y+66=0

We move all terms containing y to the left, all other terms to the right

-240y=-66

y=-66/-240

y=11/40

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