64+(4(3x+2))=180

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Solution for 64+(4(3x+2))=180 equation: 



64+(4(3x+2))=180

We move all terms to the left:

64+(4(3x+2))-(180)=0

We add all the numbers together, and all the variables

(4(3x+2))-116=0



We calculate terms in parentheses: +(4(3x+2)), so:

4(3x+2)

We multiply parentheses

12x+8

Back to the equation:

+(12x+8)



We get rid of parentheses

12x+8-116=0

We add all the numbers together, and all the variables

12x-108=0

We move all terms containing x to the left, all other terms to the right

12x=108

x=108/12

x=9

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