64-(3x-4)=4x

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Solution for 64-(3x-4)=4x equation: 



64-(3x-4)=4x

We move all terms to the left:

64-(3x-4)-(4x)=0

We add all the numbers together, and all the variables

-4x-(3x-4)+64=0

We get rid of parentheses

-4x-3x+4+64=0

We add all the numbers together, and all the variables

-7x+68=0

We move all terms containing x to the left, all other terms to the right

-7x=-68

x=-68/-7

x=9+5/7

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