64-16x=32x2

Solution for 64-16x=32x2 equation:

64-16x=32x^2

We move all terms to the left:

64-16x-(32x^2)=0

determiningTheFunctionDomain
-32x^2-16x+64=0

a = -32; b = -16; c = +64;
Δ = b2-4ac
Δ = -162-4·(-32)·64
Δ = 8448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8448}=\sqrt{256*33}=\sqrt{256}*\sqrt{33}=16\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16\sqrt{33}}{2*-32}=\frac{16-16\sqrt{33}}{-64}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16\sqrt{33}}{2*-32}=\frac{16+16\sqrt{33}}{-64}
$