64-7z=3(z-2)

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Solution for 64-7z=3(z-2) equation: 



64-7z=3(z-2)

We move all terms to the left:

64-7z-(3(z-2))=0



We calculate terms in parentheses: -(3(z-2)), so:

3(z-2)

We multiply parentheses

3z-6

Back to the equation:

-(3z-6)



We get rid of parentheses

-7z-3z+6+64=0

We add all the numbers together, and all the variables

-10z+70=0

We move all terms containing z to the left, all other terms to the right

-10z=-70

z=-70/-10

z=+7

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