64.10+27.03y(0.003059-y)=100-18.87y(1+y)

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Solution for 64.10+27.03y(0.003059-y)=100-18.87y(1+y) equation:



64.10+27.03y(0.003059-y)=100-18.87y(1+y)
We move all terms to the left:
64.10+27.03y(0.003059-y)-(100-18.87y(1+y))=0
We add all the numbers together, and all the variables
27.03y(-1y+0.003059)-(100-18.87y(y+1))+64.10=0
We add all the numbers together, and all the variables
27.03y(-1y+0.003059)-(100-18.87y(y+1))+64.1=0
We multiply parentheses
-27y^2+0.082593y-(100-18.87y(y+1))+64.1=0
We calculate terms in parentheses: -(100-18.87y(y+1)), so:
100-18.87y(y+1)
determiningTheFunctionDomain -18.87y(y+1)+100
We multiply parentheses
-18y^2-18y+100
Back to the equation:
-(-18y^2-18y+100)
We get rid of parentheses
-27y^2+18y^2+18y+0.082593y-100+64.1=0
We add all the numbers together, and all the variables
-9y^2+18.082593y-35.9=0
a = -9; b = 18.082593; c = -35.9;
Δ = b2-4ac
Δ = 18.0825932-4·(-9)·(-35.9)
Δ = -965.41983039635
Delta is less than zero, so there is no solution for the equation

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