64.52+22.22y(0.004534-y)=100-15.38y(1+y)

Solution for 64.52+22.22y(0.004534-y)=100-15.38y(1+y) equation:

64.52+22.22y(0.004534-y)=100-15.38y(1+y)

We move all terms to the left:

64.52+22.22y(0.004534-y)-(100-15.38y(1+y))=0

We add all the numbers together, and all the variables

22.22y(-1y+0.004534)-(100-15.38y(y+1))+64.52=0

We multiply parentheses

-22y^2+0.099748y-(100-15.38y(y+1))+64.52=0


We calculate terms in parentheses: -(100-15.38y(y+1)), so:

100-15.38y(y+1)

determiningTheFunctionDomain
-15.38y(y+1)+100

We multiply parentheses

-15y^2-15y+100

Back to the equation:

-(-15y^2-15y+100)


We get rid of parentheses

-22y^2+15y^2+15y+0.099748y-100+64.52=0

We add all the numbers together, and all the variables

-7y^2+15.099748y-35.48=0

a = -7; b = 15.099748; c = -35.48;
Δ = b2-4ac
Δ = 15.0997482-4·(-7)·(-35.48)
Δ = -765.4376103365
Delta is less than zero, so there is no solution for the equation