64.52+25y(0.002976-y)=100-20.83y(1+y)

Solution for 64.52+25y(0.002976-y)=100-20.83y(1+y) equation:

64.52+25y(0.002976-y)=100-20.83y(1+y)

We move all terms to the left:

64.52+25y(0.002976-y)-(100-20.83y(1+y))=0

We add all the numbers together, and all the variables

25y(-1y+0.002976)-(100-20.83y(y+1))+64.52=0

We multiply parentheses

-25y^2+0.0744y-(100-20.83y(y+1))+64.52=0


We calculate terms in parentheses: -(100-20.83y(y+1)), so:

100-20.83y(y+1)

determiningTheFunctionDomain
-20.83y(y+1)+100

We multiply parentheses

-20y^2-20y+100

Back to the equation:

-(-20y^2-20y+100)


We get rid of parentheses

-25y^2+20y^2+20y+0.0744y-100+64.52=0

We add all the numbers together, and all the variables

-5y^2+20.0744y-35.48=0

a = -5; b = 20.0744; c = -35.48;
Δ = b2-4ac
Δ = 20.07442-4·(-5)·(-35.48)
Δ = -306.61846464
Delta is less than zero, so there is no solution for the equation