64/(m+12)=m

Solution for 64/(m+12)=m equation:

64/(m+12)=m

We move all terms to the left:

64/(m+12)-(m)=0


Domain of the equation: (m+12)!=0

We move all terms containing m to the left, all other terms to the right

m!=-12

m∈R


We add all the numbers together, and all the variables

-1m+64/(m+12)=0

We multiply all the terms by the denominator


-1m*(m+12)+64=0

We multiply parentheses

-m^2-12m+64=0

We add all the numbers together, and all the variables

-1m^2-12m+64=0

a = -1; b = -12; c = +64;
Δ = b2-4ac
Δ = -122-4·(-1)·64
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-20}{2*-1}=\frac{-8}{-2}
=+4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+20}{2*-1}=\frac{32}{-2}
=-16
$