64/x+17=2x+9

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Solution for 64/x+17=2x+9 equation:



64/x+17=2x+9
We move all terms to the left:
64/x+17-(2x+9)=0
Domain of the equation: x!=0
x∈R
We get rid of parentheses
64/x-2x-9+17=0
We multiply all the terms by the denominator
-2x*x-9*x+17*x+64=0
We add all the numbers together, and all the variables
8x-2x*x+64=0
Wy multiply elements
-2x^2+8x+64=0
a = -2; b = 8; c = +64;
Δ = b2-4ac
Δ = 82-4·(-2)·64
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24}{2*-2}=\frac{-32}{-4} =+8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24}{2*-2}=\frac{16}{-4} =-4 $

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