64=((x-0)*12+(a-0)+0)

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Solution for 64=((x-0)*12+(a-0)+0) equation:


Simplifying
64 = ((x + 0) * 12 + (a + 0) + 0)

Reorder the terms:
64 = ((0 + x) * 12 + (a + 0) + 0)
Remove the zero:
64 = ((x) * 12 + (a + 0) + 0)

Reorder the terms for easier multiplication:
64 = (12x + (a + 0) + 0)

Reorder the terms:
64 = (12x + (0 + a) + 0)
Remove the zero:
64 = (12x + (a) + 0)
64 = (12x + a + 0)

Reorder the terms:
64 = (0 + a + 12x)
Remove the zero:
64 = (a + 12x)

Remove parenthesis around (a + 12x)
64 = a + 12x

Solving
64 = a + 12x

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1a' to each side of the equation.
64 + -1a = a + -1a + 12x

Combine like terms: a + -1a = 0
64 + -1a = 0 + 12x
64 + -1a = 12x

Add '-64' to each side of the equation.
64 + -64 + -1a = -64 + 12x

Combine like terms: 64 + -64 = 0
0 + -1a = -64 + 12x
-1a = -64 + 12x

Divide each side by '-1'.
a = 64 + -12x

Simplifying
a = 64 + -12x

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