64=(3x-2)(x-2)

Solution for 64=(3x-2)(x-2) equation:

64=(3x-2)(x-2)

We move all terms to the left:

64-((3x-2)(x-2))=0

We multiply parentheses ..

-((+3x^2-6x-2x+4))+64=0


We calculate terms in parentheses: -((+3x^2-6x-2x+4)), so:

(+3x^2-6x-2x+4)

We get rid of parentheses

3x^2-6x-2x+4

We add all the numbers together, and all the variables

3x^2-8x+4

Back to the equation:

-(3x^2-8x+4)


We get rid of parentheses

-3x^2+8x-4+64=0

We add all the numbers together, and all the variables

-3x^2+8x+60=0

a = -3; b = 8; c = +60;
Δ = b2-4ac
Δ = 82-4·(-3)·60
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-28}{2*-3}=\frac{-36}{-6}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+28}{2*-3}=\frac{20}{-6}
=-3+1/3
$