64=(7/3x)

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Solution for 64=(7/3x) equation: 



64=(7/3x)

We move all terms to the left:

64-((7/3x))=0



Domain of the equation: 3x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+7/3x))+64=0

We multiply all the terms by the denominator


-((+7+64*3x))=0



We calculate terms in parentheses: -((+7+64*3x)), so:

(+7+64*3x)

We add all the numbers together, and all the variables

(64*3x+7)

We get rid of parentheses

64*3x+7

Wy multiply elements

192x+7

Back to the equation:

-(192x+7)



We get rid of parentheses

-192x-7=0

We move all terms containing x to the left, all other terms to the right

-192x=7

x=7/-192

x=-7/192

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